A boy reaches out of a window and tosses a ball straight up with a speed of 6.0 m/s . The ball is 22 m above the ground as he releases it?

A boy reaches out of a window and tosses a ball straight up with a speed of 6.0 m/s . The ball is 22 m above the ground as he releases it?

Part A Use energy to find the ball’s maximum height above the ground. That is, use (1/2)mv^2 = mgy. As you can see, even though you don’t know m, you can divide it on both sides of the equaiton.Express your answer to two significant figures and include the appropriate unitsPart B Use energy to find the ball’s speed as it passes the window on its way down.Express your answer to two significant figures and include the appropriate units.Part C Use energy to find the speed of impact on the ground.Express your answer to two significant figures and include the appropriate units.