A car is traveling around a horizontal circular track with radius r = 160 m at a constant speed v = 28 m/s as shown. The angle A = 22 above the x…
A car is traveling around a horizontal circular track with radius r = 160 m at a constant speed v = 28 m/s as shown. The angle θA = 22° above the x axis, and the angle θB = 58° below the x axis.
Given,r 160 m 28 ms 1 a 2 2822 4.9 msr 160 We know that centripetal acceleration will be pointing towards center. Now at A a x a sin 68 (-ve sign ∵ it’s acting towards left) 4.9 sin(680 )…
Leave a Reply
Want to join the discussion?Feel free to contribute!