# Assuming that the specic heat of salt is 0.22 Kcal/ (kg C), water is 1 Kcal/ (kg C), and ice is 0.5 Kcal! (kg C), calculate the specific heat of the…

could you please help me with this problem as soon as possible

01. Assuming that the speciﬁc heat of salt is 0.22 Kcal/ (kg °C), water is 1 Kcal/ (kg °C), and ice is 0.5 Kcal! (kg °C), calculate the specific heat of the water saltmixtures you made (use mass weighted averages). This means C (mixture) = m1C1 + m202/(m1+ m2) Here is one example: Mass of salt = 50 g Mass of water = 100 9 Plug the numbers into the equation to get C (mixture) = 0.74 Kcall (kg °C)

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